$$$\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$$ 关于$$$x$$$的积分
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您的输入
求$$$\int \frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}\, dx$$$。
解答
对 $$$c=\frac{1}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$$ 和 $$$f{\left(x \right)} = \sin{\left(5 x \right)}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$:
$${\color{red}{\int{\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} d x}}} = {\color{red}{\left(\frac{\int{\sin{\left(5 x \right)} d x}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}\right)}}$$
设$$$u=5 x$$$。
则$$$du=\left(5 x\right)^{\prime }dx = 5 dx$$$ (步骤见»),并有$$$dx = \frac{du}{5}$$$。
积分变为
$$\frac{{\color{red}{\int{\sin{\left(5 x \right)} d x}}}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} = \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{5} d u}}}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$
对 $$$c=\frac{1}{5}$$$ 和 $$$f{\left(u \right)} = \sin{\left(u \right)}$$$ 应用常数倍法则 $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$:
$$\frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{5} d u}}}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} = \frac{{\color{red}{\left(\frac{\int{\sin{\left(u \right)} d u}}{5}\right)}}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$
正弦函数的积分为 $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:
$$\frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{10 \sin{\left(\frac{x_{0}}{5} \right)}} = \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{10 \sin{\left(\frac{x_{0}}{5} \right)}}$$
回忆一下 $$$u=5 x$$$:
$$- \frac{\cos{\left({\color{red}{u}} \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}} = - \frac{\cos{\left({\color{red}{\left(5 x\right)}} \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}}$$
因此,
$$\int{\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} d x} = - \frac{\cos{\left(5 x \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}}$$
加上积分常数:
$$\int{\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} d x} = - \frac{\cos{\left(5 x \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}}+C$$
答案
$$$\int \frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}\, dx = - \frac{\cos{\left(5 x \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}} + C$$$A