$$$\sin{\left(3 x^{2} \right)}$$$ 的积分
您的输入
求$$$\int \sin{\left(3 x^{2} \right)}\, dx$$$。
解答
设$$$u=\sqrt{3} x$$$。
则$$$du=\left(\sqrt{3} x\right)^{\prime }dx = \sqrt{3} dx$$$ (步骤见»),并有$$$dx = \frac{\sqrt{3} du}{3}$$$。
积分变为
$${\color{red}{\int{\sin{\left(3 x^{2} \right)} d x}}} = {\color{red}{\int{\frac{\sqrt{3} \sin{\left(u^{2} \right)}}{3} d u}}}$$
对 $$$c=\frac{\sqrt{3}}{3}$$$ 和 $$$f{\left(u \right)} = \sin{\left(u^{2} \right)}$$$ 应用常数倍法则 $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$:
$${\color{red}{\int{\frac{\sqrt{3} \sin{\left(u^{2} \right)}}{3} d u}}} = {\color{red}{\left(\frac{\sqrt{3} \int{\sin{\left(u^{2} \right)} d u}}{3}\right)}}$$
该积分(菲涅耳正弦积分)没有闭式表达式:
$$\frac{\sqrt{3} {\color{red}{\int{\sin{\left(u^{2} \right)} d u}}}}{3} = \frac{\sqrt{3} {\color{red}{\left(\frac{\sqrt{2} \sqrt{\pi} S\left(\frac{\sqrt{2} u}{\sqrt{\pi}}\right)}{2}\right)}}}{3}$$
回忆一下 $$$u=\sqrt{3} x$$$:
$$\frac{\sqrt{6} \sqrt{\pi} S\left(\frac{\sqrt{2} {\color{red}{u}}}{\sqrt{\pi}}\right)}{6} = \frac{\sqrt{6} \sqrt{\pi} S\left(\frac{\sqrt{2} {\color{red}{\sqrt{3} x}}}{\sqrt{\pi}}\right)}{6}$$
因此,
$$\int{\sin{\left(3 x^{2} \right)} d x} = \frac{\sqrt{6} \sqrt{\pi} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)}{6}$$
加上积分常数:
$$\int{\sin{\left(3 x^{2} \right)} d x} = \frac{\sqrt{6} \sqrt{\pi} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)}{6}+C$$
答案
$$$\int \sin{\left(3 x^{2} \right)}\, dx = \frac{\sqrt{6} \sqrt{\pi} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)}{6} + C$$$A