$$$a l t \left(x - \pi\right) \cos{\left(x \right)}$$$ 关于$$$x$$$的积分

该计算器将求出$$$a l t \left(x - \pi\right) \cos{\left(x \right)}$$$关于$$$x$$$的积分/原函数,并显示步骤。

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您的输入

$$$\int a l t \left(x - \pi\right) \cos{\left(x \right)}\, dx$$$

解答

$$$c=a l t$$$$$$f{\left(x \right)} = \left(x - \pi\right) \cos{\left(x \right)}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$

$${\color{red}{\int{a l t \left(x - \pi\right) \cos{\left(x \right)} d x}}} = {\color{red}{a l t \int{\left(x - \pi\right) \cos{\left(x \right)} d x}}}$$

对于积分$$$\int{\left(x - \pi\right) \cos{\left(x \right)} d x}$$$,使用分部积分法$$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$

$$$\operatorname{u}=x - \pi$$$$$$\operatorname{dv}=\cos{\left(x \right)} dx$$$

$$$\operatorname{du}=\left(x - \pi\right)^{\prime }dx=1 dx$$$ (步骤见 »),并且 $$$\operatorname{v}=\int{\cos{\left(x \right)} d x}=\sin{\left(x \right)}$$$ (步骤见 »)。

所以,

$$a l t {\color{red}{\int{\left(x - \pi\right) \cos{\left(x \right)} d x}}}=a l t {\color{red}{\left(\left(x - \pi\right) \cdot \sin{\left(x \right)}-\int{\sin{\left(x \right)} \cdot 1 d x}\right)}}=a l t {\color{red}{\left(\left(x - \pi\right) \sin{\left(x \right)} - \int{\sin{\left(x \right)} d x}\right)}}$$

正弦函数的积分为 $$$\int{\sin{\left(x \right)} d x} = - \cos{\left(x \right)}$$$:

$$a l t \left(\left(x - \pi\right) \sin{\left(x \right)} - {\color{red}{\int{\sin{\left(x \right)} d x}}}\right) = a l t \left(\left(x - \pi\right) \sin{\left(x \right)} - {\color{red}{\left(- \cos{\left(x \right)}\right)}}\right)$$

因此,

$$\int{a l t \left(x - \pi\right) \cos{\left(x \right)} d x} = a l t \left(\left(x - \pi\right) \sin{\left(x \right)} + \cos{\left(x \right)}\right)$$

化简:

$$\int{a l t \left(x - \pi\right) \cos{\left(x \right)} d x} = - a l t \left(\left(\pi - x\right) \sin{\left(x \right)} - \cos{\left(x \right)}\right)$$

加上积分常数:

$$\int{a l t \left(x - \pi\right) \cos{\left(x \right)} d x} = - a l t \left(\left(\pi - x\right) \sin{\left(x \right)} - \cos{\left(x \right)}\right)+C$$

答案

$$$\int a l t \left(x - \pi\right) \cos{\left(x \right)}\, dx = - a l t \left(\left(\pi - x\right) \sin{\left(x \right)} - \cos{\left(x \right)}\right) + C$$$A