$$$\frac{1003605945944011425233769242881280649744658171441 t}{1000000000000000000000000000000000000000000000000}$$$ 的积分
相关计算器: 定积分与广义积分计算器
您的输入
求$$$\int \frac{1003605945944011425233769242881280649744658171441 t}{1000000000000000000000000000000000000000000000000}\, dt$$$。
解答
对 $$$c=\frac{1003605945944011425233769242881280649744658171441}{1000000000000000000000000000000000000000000000000}$$$ 和 $$$f{\left(t \right)} = t$$$ 应用常数倍法则 $$$\int c f{\left(t \right)}\, dt = c \int f{\left(t \right)}\, dt$$$：
$${\color{red}{\int{\frac{1003605945944011425233769242881280649744658171441 t}{1000000000000000000000000000000000000000000000000} d t}}} = {\color{red}{\left(\frac{1003605945944011425233769242881280649744658171441 \int{t d t}}{1000000000000000000000000000000000000000000000000}\right)}}$$
应用幂法则 $$$\int t^{n}\, dt = \frac{t^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$，其中 $$$n=1$$$：
$$\frac{1003605945944011425233769242881280649744658171441 {\color{red}{\int{t d t}}}}{1000000000000000000000000000000000000000000000000}=\frac{1003605945944011425233769242881280649744658171441 {\color{red}{\frac{t^{1 + 1}}{1 + 1}}}}{1000000000000000000000000000000000000000000000000}=\frac{1003605945944011425233769242881280649744658171441 {\color{red}{\left(\frac{t^{2}}{2}\right)}}}{1000000000000000000000000000000000000000000000000}$$
因此，
$$\int{\frac{1003605945944011425233769242881280649744658171441 t}{1000000000000000000000000000000000000000000000000} d t} = \frac{1003605945944011425233769242881280649744658171441 t^{2}}{2000000000000000000000000000000000000000000000000}$$
加上积分常数：
$$\int{\frac{1003605945944011425233769242881280649744658171441 t}{1000000000000000000000000000000000000000000000000} d t} = \frac{1003605945944011425233769242881280649744658171441 t^{2}}{2000000000000000000000000000000000000000000000000}+C$$
答案
$$$\int \frac{1003605945944011425233769242881280649744658171441 t}{1000000000000000000000000000000000000000000000000}\, dt = \frac{1003605945944011425233769242881280649744658171441 t^{2}}{2000000000000000000000000000000000000000000000000} + C$$$A