$$$\frac{x^{5} - 4}{x^{22}}$$$ 的积分

求$$$\int \frac{x^{5} - 4}{x^{22}}\, dx$$$。

Expand the expression:

$${\color{red}{\int{\frac{x^{5} - 4}{x^{22}} d x}}} = {\color{red}{\int{\left(\frac{1}{x^{17}} - \frac{4}{x^{22}}\right)d x}}}$$

逐项积分：

$${\color{red}{\int{\left(\frac{1}{x^{17}} - \frac{4}{x^{22}}\right)d x}}} = {\color{red}{\left(- \int{\frac{4}{x^{22}} d x} + \int{\frac{1}{x^{17}} d x}\right)}}$$

应用幂法则 $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$，其中 $$$n=-17$$$：

$$- \int{\frac{4}{x^{22}} d x} + {\color{red}{\int{\frac{1}{x^{17}} d x}}}=- \int{\frac{4}{x^{22}} d x} + {\color{red}{\int{x^{-17} d x}}}=- \int{\frac{4}{x^{22}} d x} + {\color{red}{\frac{x^{-17 + 1}}{-17 + 1}}}=- \int{\frac{4}{x^{22}} d x} + {\color{red}{\left(- \frac{x^{-16}}{16}\right)}}=- \int{\frac{4}{x^{22}} d x} + {\color{red}{\left(- \frac{1}{16 x^{16}}\right)}}$$

对 $$$c=4$$$ 和 $$$f{\left(x \right)} = \frac{1}{x^{22}}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$：

$$- {\color{red}{\int{\frac{4}{x^{22}} d x}}} - \frac{1}{16 x^{16}} = - {\color{red}{\left(4 \int{\frac{1}{x^{22}} d x}\right)}} - \frac{1}{16 x^{16}}$$

应用幂法则 $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$，其中 $$$n=-22$$$：

$$- 4 {\color{red}{\int{\frac{1}{x^{22}} d x}}} - \frac{1}{16 x^{16}}=- 4 {\color{red}{\int{x^{-22} d x}}} - \frac{1}{16 x^{16}}=- 4 {\color{red}{\frac{x^{-22 + 1}}{-22 + 1}}} - \frac{1}{16 x^{16}}=- 4 {\color{red}{\left(- \frac{x^{-21}}{21}\right)}} - \frac{1}{16 x^{16}}=- 4 {\color{red}{\left(- \frac{1}{21 x^{21}}\right)}} - \frac{1}{16 x^{16}}$$

因此，

$$\int{\frac{x^{5} - 4}{x^{22}} d x} = - \frac{1}{16 x^{16}} + \frac{4}{21 x^{21}}$$

化简：

$$\int{\frac{x^{5} - 4}{x^{22}} d x} = \frac{64 - 21 x^{5}}{336 x^{21}}$$

加上积分常数：

$$\int{\frac{x^{5} - 4}{x^{22}} d x} = \frac{64 - 21 x^{5}}{336 x^{21}}+C$$

$$$\int \frac{x^{5} - 4}{x^{22}}\, dx = \frac{64 - 21 x^{5}}{336 x^{21}} + C$$$A