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Solution
Your input: find $$$\frac{408}{160}$$$ using long division.
Write the problem in the special format:
$$$\require{enclose}\begin{array}{rlc}&\phantom{-\enclose{longdiv}{}}\begin{array}{ccc}\phantom{0}&\phantom{0}&\phantom{2}\end{array}&\\160&\phantom{-}\enclose{longdiv}{\begin{array}{ccc}4&0&8\end{array}}&\\&\begin{array}{lll}\end{array}&\begin{array}{c}\end{array}\end{array}$$$
Step 1
How many $$$160$$$'s are in $$$4$$$?
The answer is $$$0$$$.
Write down $$$0$$$ in the upper part of the table.
Now, $$$4-160 \cdot 0 = 4 - 0= 4$$$.
Bring down the next digit of the dividend.
$$$\require{enclose}\begin{array}{rlc}&\phantom{-\enclose{longdiv}{}}\begin{array}{ccc}\color{Chartreuse}{0}&\phantom{0}&\phantom{2}\end{array}&\\\color{Magenta}{160}&\phantom{-}\enclose{longdiv}{\begin{array}{ccc}\color{Chartreuse}{4}& 0 \downarrow&8\end{array}}&\\&\begin{array}{lll}-&\phantom{0}&\phantom{8}\\\phantom{lll}0\\\hline\phantom{lll}4&0\end{array}&\begin{array}{c}\end{array}\end{array}$$$
Step 2
How many $$$160$$$'s are in $$$40$$$?
The answer is $$$0$$$.
Write down $$$0$$$ in the upper part of the table.
Now, $$$40-160 \cdot 0 = 40 - 0= 40$$$.
Bring down the next digit of the dividend.
$$$\require{enclose}\begin{array}{rlc}&\phantom{-\enclose{longdiv}{}}\begin{array}{ccc}0&\color{Violet}{0}&\phantom{2}\end{array}&\\\color{Magenta}{160}&\phantom{-}\enclose{longdiv}{\begin{array}{ccc}4&0& 8 \downarrow\end{array}}&\\&\begin{array}{lll}-&\phantom{0}&\phantom{8}\\\phantom{lll}0\\\hline\phantom{lll}\color{Violet}{4}&\color{Violet}{0}\\-&\phantom{0}&\phantom{8}\\\phantom{lll}&0\\\hline\phantom{lll}4&0&8\end{array}&\begin{array}{c}\end{array}\end{array}$$$
Step 3
How many $$$160$$$'s are in $$$408$$$?
The answer is $$$2$$$.
Write down $$$2$$$ in the upper part of the table.
Now, $$$408-160 \cdot 2 = 408 - 320= 88$$$.
$$$\require{enclose}\begin{array}{rlc}&\phantom{-\enclose{longdiv}{}}\begin{array}{ccc}0&0&\color{Chocolate}{2}\end{array}&\\\color{Magenta}{160}&\phantom{-}\enclose{longdiv}{\begin{array}{ccc}4&0&8\end{array}}&\\&\begin{array}{lll}-&\phantom{0}&\phantom{8}\\\phantom{lll}0\\\hline\phantom{lll}4&0\\-&\phantom{0}&\phantom{8}\\\phantom{lll}&0\\\hline\phantom{lll}\color{Chocolate}{4}&\color{Chocolate}{0}&\color{Chocolate}{8}\\-&\phantom{0}&\phantom{8}\\\phantom{lll}3&2&0\\\hline\phantom{lll}&8&8\end{array}&\begin{array}{c}\end{array}\end{array}$$$
Since the remainder is less than the divisor, we are done.
Therefore, $$$\frac{408}{160}=2+\frac{88}{160}=2+\frac{11}{20}$$$
Answer: $$$\frac{408}{160}=2+\frac{11}{20}$$$