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  1. 홈
  2. 계산기
  3. 계산기: 미적분학 III
  4. 미적분 계산기

편도함수 계산기

편도함수를 단계별로 계산

이 온라인 계산기는 풀이 과정을 보여 주면서 함수의 편미분을 계산합니다. 적분의 순서는 임의로 지정할 수 있습니다.

Enter a function:

Enter the order of integration:

Hint: type x^2,y to calculate `(partial^3 f)/(partial x^2 partial y)`, or enter x,y^2,x to find `(partial^4 f)/(partial x partial y^2 partial x)`.

If the calculator did not compute something or you have identified an error, or you have a suggestion/feedback, please contact us.

Solution

Your input: find $$$\frac{\partial}{\partial y}\left(x^{2} + y^{2} + z^{2} - 14\right)$$$

The derivative of a sum/difference is the sum/difference of derivatives:

$${\color{red}{\frac{\partial}{\partial y}\left(x^{2} + y^{2} + z^{2} - 14\right)}}={\color{red}{\left(- \frac{\partial}{\partial y}\left(14\right) + \frac{\partial}{\partial y}\left(x^{2}\right) + \frac{\partial}{\partial y}\left(y^{2}\right) + \frac{\partial}{\partial y}\left(z^{2}\right)\right)}}$$

The derivative of a constant is 0:

$${\color{red}{\frac{\partial}{\partial y}\left(z^{2}\right)}} - \frac{\partial}{\partial y}\left(14\right) + \frac{\partial}{\partial y}\left(x^{2}\right) + \frac{\partial}{\partial y}\left(y^{2}\right)={\color{red}{\left(0\right)}} - \frac{\partial}{\partial y}\left(14\right) + \frac{\partial}{\partial y}\left(x^{2}\right) + \frac{\partial}{\partial y}\left(y^{2}\right)$$

The derivative of a constant is 0:

$$- {\color{red}{\frac{\partial}{\partial y}\left(14\right)}} + \frac{\partial}{\partial y}\left(x^{2}\right) + \frac{\partial}{\partial y}\left(y^{2}\right)=- {\color{red}{\left(0\right)}} + \frac{\partial}{\partial y}\left(x^{2}\right) + \frac{\partial}{\partial y}\left(y^{2}\right)$$

The derivative of a constant is 0:

$${\color{red}{\frac{\partial}{\partial y}\left(x^{2}\right)}} + \frac{\partial}{\partial y}\left(y^{2}\right)={\color{red}{\left(0\right)}} + \frac{\partial}{\partial y}\left(y^{2}\right)$$

Apply the power rule $$$\frac{\partial}{\partial y} \left(y^{n} \right)=n\cdot y^{-1+n}$$$ with $$$n=2$$$:

$${\color{red}{\frac{\partial}{\partial y}\left(y^{2}\right)}}={\color{red}{\left(2 y^{-1 + 2}\right)}}=2 y$$

Thus, $$$\frac{\partial}{\partial y}\left(x^{2} + y^{2} + z^{2} - 14\right)=2 y$$$

Answer: $$$\frac{\partial}{\partial y}\left(x^{2} + y^{2} + z^{2} - 14\right)=2 y$$$


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