$$$- \frac{5228171817}{100000000} - i$$$의 극형식
사용자 입력
$$$- \frac{5228171817}{100000000} - i$$$의 극형식을 구하세요.
풀이
복소수의 표준형은 $$$- \frac{5228171817}{100000000} - i$$$입니다.
복소수 $$$a + b i$$$에 대해 극형식은 $$$r \left(\cos{\left(\theta \right)} + i \sin{\left(\theta \right)}\right)$$$로 주어지며, 여기서 $$$r = \sqrt{a^{2} + b^{2}}$$$ 및 $$$\theta = \operatorname{atan}{\left(\frac{b}{a} \right)}$$$.
다음이 성립한다: $$$a = - \frac{5228171817}{100000000}$$$ 및 $$$b = -1$$$.
따라서, $$$r = \sqrt{\left(- \frac{5228171817}{100000000}\right)^{2} + \left(-1\right)^{2}} = \frac{\sqrt{27343780548073081489}}{100000000}.$$$
또한, $$$\theta = \operatorname{atan}{\left(\frac{-1}{- \frac{5228171817}{100000000}} \right)} - \pi = - \pi + \operatorname{atan}{\left(\frac{100000000}{5228171817} \right)}.$$$
따라서 $$$- \frac{5228171817}{100000000} - i = \frac{\sqrt{27343780548073081489}}{100000000} \left(\cos{\left(- \pi + \operatorname{atan}{\left(\frac{100000000}{5228171817} \right)} \right)} + i \sin{\left(- \pi + \operatorname{atan}{\left(\frac{100000000}{5228171817} \right)} \right)}\right).$$$
정답
$$$- \frac{5228171817}{100000000} - i = \frac{\sqrt{27343780548073081489}}{100000000} \left(\cos{\left(- \pi + \operatorname{atan}{\left(\frac{100000000}{5228171817} \right)} \right)} + i \sin{\left(- \pi + \operatorname{atan}{\left(\frac{100000000}{5228171817} \right)} \right)}\right) = \frac{\sqrt{27343780548073081489}}{100000000} \left(\cos{\left(\left(\frac{- 180 \pi + 180 \operatorname{atan}{\left(\frac{100000000}{5228171817} \right)}}{\pi}\right)^{\circ} \right)} + i \sin{\left(\left(\frac{- 180 \pi + 180 \operatorname{atan}{\left(\frac{100000000}{5228171817} \right)}}{\pi}\right)^{\circ} \right)}\right)$$$A