Calcolatore di integrali definiti e impropri

Il calcolatore cercherà di valutare l'integrale definito (cioè con estremi), inclusi quelli impropri, mostrando i passaggi.

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Solution

Your input: calculate $$$\int_{0}^{1}\left( - \frac{3 x^{2}}{2} + 3 x \right)dx$$$

First, calculate the corresponding indefinite integral: $$$\int{\left(- \frac{3 x^{2}}{2} + 3 x\right)d x}=\frac{x^{2} \left(3 - x\right)}{2}$$$ (for steps, see indefinite integral calculator)

According to the Fundamental Theorem of Calculus, $$$\int_a^b F(x) dx=f(b)-f(a)$$$, so just evaluate the integral at the endpoints, and that's the answer.

$$$\left(\frac{x^{2} \left(3 - x\right)}{2}\right)|_{\left(x=1\right)}=1$$$

$$$\left(\frac{x^{2} \left(3 - x\right)}{2}\right)|_{\left(x=0\right)}=0$$$

$$$\int_{0}^{1}\left( - \frac{3 x^{2}}{2} + 3 x \right)dx=\left(\frac{x^{2} \left(3 - x\right)}{2}\right)|_{\left(x=1\right)}-\left(\frac{x^{2} \left(3 - x\right)}{2}\right)|_{\left(x=0\right)}=1$$$

Answer: $$$\int_{0}^{1}\left( - \frac{3 x^{2}}{2} + 3 x \right)dx=1$$$

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Solution