Kalkulator Integral Tentu dan Tak Wajar
Hitung integral tentu dan tak wajar langkah demi langkah
Kalkulator akan mencoba mengevaluasi integral tentu (yaitu dengan batas-batas), termasuk integral tak wajar, dengan menampilkan langkah-langkahnya.
Solution
Your input: calculate $$$\int_{0}^{1}\left( \sqrt{1 - y^{2}} \right)dy$$$
First, calculate the corresponding indefinite integral: $$$\int{\sqrt{1 - y^{2}} d y}=\frac{y \sqrt{1 - y^{2}}}{2} + \frac{\operatorname{asin}{\left(y \right)}}{2}$$$ (for steps, see indefinite integral calculator)
According to the Fundamental Theorem of Calculus, $$$\int_a^b F(x) dx=f(b)-f(a)$$$, so just evaluate the integral at the endpoints, and that's the answer.
$$$\left(\frac{y \sqrt{1 - y^{2}}}{2} + \frac{\operatorname{asin}{\left(y \right)}}{2}\right)|_{\left(y=1\right)}=\frac{\pi}{4}$$$
$$$\left(\frac{y \sqrt{1 - y^{2}}}{2} + \frac{\operatorname{asin}{\left(y \right)}}{2}\right)|_{\left(y=0\right)}=0$$$
$$$\int_{0}^{1}\left( \sqrt{1 - y^{2}} \right)dy=\left(\frac{y \sqrt{1 - y^{2}}}{2} + \frac{\operatorname{asin}{\left(y \right)}}{2}\right)|_{\left(y=1\right)}-\left(\frac{y \sqrt{1 - y^{2}}}{2} + \frac{\operatorname{asin}{\left(y \right)}}{2}\right)|_{\left(y=0\right)}=\frac{\pi}{4}$$$
Answer: $$$\int_{0}^{1}\left( \sqrt{1 - y^{2}} \right)dy=\frac{\pi}{4}\approx 0.785398163397448$$$