Integral de $$$x - \frac{1}{x}$$$

Halla $$$\int \left(x - \frac{1}{x}\right)\, dx$$$.

Integra término a término:

$${\color{red}{\int{\left(x - \frac{1}{x}\right)d x}}} = {\color{red}{\left(- \int{\frac{1}{x} d x} + \int{x d x}\right)}}$$

Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=1$$$:

$$- \int{\frac{1}{x} d x} + {\color{red}{\int{x d x}}}=- \int{\frac{1}{x} d x} + {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=- \int{\frac{1}{x} d x} + {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

La integral de $$$\frac{1}{x}$$$ es $$$\int{\frac{1}{x} d x} = \ln{\left(\left|{x}\right| \right)}$$$:

$$\frac{x^{2}}{2} - {\color{red}{\int{\frac{1}{x} d x}}} = \frac{x^{2}}{2} - {\color{red}{\ln{\left(\left|{x}\right| \right)}}}$$

Por lo tanto,

$$\int{\left(x - \frac{1}{x}\right)d x} = \frac{x^{2}}{2} - \ln{\left(\left|{x}\right| \right)}$$

Añade la constante de integración:

$$\int{\left(x - \frac{1}{x}\right)d x} = \frac{x^{2}}{2} - \ln{\left(\left|{x}\right| \right)}+C$$

$$$\int \left(x - \frac{1}{x}\right)\, dx = \left(\frac{x^{2}}{2} - \ln\left(\left|{x}\right|\right)\right) + C$$$A