Integral de $$$- x + \ln\left(2\right)$$$

Halla $$$\int \left(- x + \ln\left(2\right)\right)\, dx$$$.

Integra término a término:

$${\color{red}{\int{\left(- x + \ln{\left(2 \right)}\right)d x}}} = {\color{red}{\left(- \int{x d x} + \int{\ln{\left(2 \right)} d x}\right)}}$$

Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=1$$$:

$$\int{\ln{\left(2 \right)} d x} - {\color{red}{\int{x d x}}}=\int{\ln{\left(2 \right)} d x} - {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=\int{\ln{\left(2 \right)} d x} - {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

Aplica la regla de la constante $$$\int c\, dx = c x$$$ con $$$c=\ln{\left(2 \right)}$$$:

$$- \frac{x^{2}}{2} + {\color{red}{\int{\ln{\left(2 \right)} d x}}} = - \frac{x^{2}}{2} + {\color{red}{x \ln{\left(2 \right)}}}$$

Por lo tanto,

$$\int{\left(- x + \ln{\left(2 \right)}\right)d x} = - \frac{x^{2}}{2} + x \ln{\left(2 \right)}$$

Simplificar:

$$\int{\left(- x + \ln{\left(2 \right)}\right)d x} = \frac{x \left(- x + 2 \ln{\left(2 \right)}\right)}{2}$$

Añade la constante de integración:

$$\int{\left(- x + \ln{\left(2 \right)}\right)d x} = \frac{x \left(- x + 2 \ln{\left(2 \right)}\right)}{2}+C$$

$$$\int \left(- x + \ln\left(2\right)\right)\, dx = \frac{x \left(- x + 2 \ln\left(2\right)\right)}{2} + C$$$A