Integral de $$$2 y$$$

Halla $$$\int 2 y\, dy$$$.

Aplica la regla del factor constante $$$\int c f{\left(y \right)}\, dy = c \int f{\left(y \right)}\, dy$$$ con $$$c=2$$$ y $$$f{\left(y \right)} = y$$$:

$${\color{red}{\int{2 y d y}}} = {\color{red}{\left(2 \int{y d y}\right)}}$$

Aplica la regla de la potencia $$$\int y^{n}\, dy = \frac{y^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=1$$$:

$$2 {\color{red}{\int{y d y}}}=2 {\color{red}{\frac{y^{1 + 1}}{1 + 1}}}=2 {\color{red}{\left(\frac{y^{2}}{2}\right)}}$$

Por lo tanto,

$$\int{2 y d y} = y^{2}$$

Añade la constante de integración:

$$\int{2 y d y} = y^{2}+C$$

$$$\int 2 y\, dy = y^{2} + C$$$A