Integral de $$$\frac{1}{x \sqrt{x^{2} - 1}}$$$
Calculadora relacionada: Calculadora de integrales definidas e impropias
Tu entrada
Halla $$$\int \frac{1}{x \sqrt{x^{2} - 1}}\, dx$$$.
Solución
Sea $$$u=\frac{1}{x}$$$.
Entonces $$$du=\left(\frac{1}{x}\right)^{\prime }dx = - \frac{1}{x^{2}} dx$$$ (los pasos pueden verse »), y obtenemos que $$$\frac{dx}{x^{2}} = - du$$$.
Entonces,
$${\color{red}{\int{\frac{1}{x \sqrt{x^{2} - 1}} d x}}} = {\color{red}{\int{\left(- \frac{1}{\sqrt{1 - u^{2}}}\right)d u}}}$$
Aplica la regla del factor constante $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ con $$$c=-1$$$ y $$$f{\left(u \right)} = \frac{1}{\sqrt{1 - u^{2}}}$$$:
$${\color{red}{\int{\left(- \frac{1}{\sqrt{1 - u^{2}}}\right)d u}}} = {\color{red}{\left(- \int{\frac{1}{\sqrt{1 - u^{2}}} d u}\right)}}$$
Sea $$$u=\sin{\left(v \right)}$$$.
Entonces $$$du=\left(\sin{\left(v \right)}\right)^{\prime }dv = \cos{\left(v \right)} dv$$$ (los pasos pueden verse »).
Además, se sigue que $$$v=\operatorname{asin}{\left(u \right)}$$$.
Por lo tanto,
$$$\frac{1}{\sqrt{1 - u ^{2}}} = \frac{1}{\sqrt{1 - \sin^{2}{\left( v \right)}}}$$$
Utiliza la identidad $$$1 - \sin^{2}{\left( v \right)} = \cos^{2}{\left( v \right)}$$$:
$$$\frac{1}{\sqrt{1 - \sin^{2}{\left( v \right)}}}=\frac{1}{\sqrt{\cos^{2}{\left( v \right)}}}$$$
Suponiendo que $$$\cos{\left( v \right)} \ge 0$$$, obtenemos lo siguiente:
$$$\frac{1}{\sqrt{\cos^{2}{\left( v \right)}}} = \frac{1}{\cos{\left( v \right)}}$$$
La integral se convierte en
$$- {\color{red}{\int{\frac{1}{\sqrt{1 - u^{2}}} d u}}} = - {\color{red}{\int{1 d v}}}$$
Aplica la regla de la constante $$$\int c\, dv = c v$$$ con $$$c=1$$$:
$$- {\color{red}{\int{1 d v}}} = - {\color{red}{v}}$$
Recordemos que $$$v=\operatorname{asin}{\left(u \right)}$$$:
$$- {\color{red}{v}} = - {\color{red}{\operatorname{asin}{\left(u \right)}}}$$
Recordemos que $$$u=\frac{1}{x}$$$:
$$- \operatorname{asin}{\left({\color{red}{u}} \right)} = - \operatorname{asin}{\left({\color{red}{\frac{1}{x}}} \right)}$$
Por lo tanto,
$$\int{\frac{1}{x \sqrt{x^{2} - 1}} d x} = - \operatorname{asin}{\left(\frac{1}{x} \right)}$$
Añade la constante de integración:
$$\int{\frac{1}{x \sqrt{x^{2} - 1}} d x} = - \operatorname{asin}{\left(\frac{1}{x} \right)}+C$$
Respuesta
$$$\int \frac{1}{x \sqrt{x^{2} - 1}}\, dx = - \operatorname{asin}{\left(\frac{1}{x} \right)} + C$$$A