Integral de $$$\frac{x^{5}}{15} - \frac{x^{3}}{3} + x$$$
Calculadora relacionada: Calculadora de integrales definidas e impropias
Tu entrada
Halla $$$\int \left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)\, dx$$$.
Solución
Integra término a término:
$${\color{red}{\int{\left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)d x}}} = {\color{red}{\left(\int{x d x} - \int{\frac{x^{3}}{3} d x} + \int{\frac{x^{5}}{15} d x}\right)}}$$
Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=1$$$:
$$- \int{\frac{x^{3}}{3} d x} + \int{\frac{x^{5}}{15} d x} + {\color{red}{\int{x d x}}}=- \int{\frac{x^{3}}{3} d x} + \int{\frac{x^{5}}{15} d x} + {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=- \int{\frac{x^{3}}{3} d x} + \int{\frac{x^{5}}{15} d x} + {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$
Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=\frac{1}{3}$$$ y $$$f{\left(x \right)} = x^{3}$$$:
$$\frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - {\color{red}{\int{\frac{x^{3}}{3} d x}}} = \frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - {\color{red}{\left(\frac{\int{x^{3} d x}}{3}\right)}}$$
Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=3$$$:
$$\frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - \frac{{\color{red}{\int{x^{3} d x}}}}{3}=\frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - \frac{{\color{red}{\frac{x^{1 + 3}}{1 + 3}}}}{3}=\frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - \frac{{\color{red}{\left(\frac{x^{4}}{4}\right)}}}{3}$$
Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=\frac{1}{15}$$$ y $$$f{\left(x \right)} = x^{5}$$$:
$$- \frac{x^{4}}{12} + \frac{x^{2}}{2} + {\color{red}{\int{\frac{x^{5}}{15} d x}}} = - \frac{x^{4}}{12} + \frac{x^{2}}{2} + {\color{red}{\left(\frac{\int{x^{5} d x}}{15}\right)}}$$
Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=5$$$:
$$- \frac{x^{4}}{12} + \frac{x^{2}}{2} + \frac{{\color{red}{\int{x^{5} d x}}}}{15}=- \frac{x^{4}}{12} + \frac{x^{2}}{2} + \frac{{\color{red}{\frac{x^{1 + 5}}{1 + 5}}}}{15}=- \frac{x^{4}}{12} + \frac{x^{2}}{2} + \frac{{\color{red}{\left(\frac{x^{6}}{6}\right)}}}{15}$$
Por lo tanto,
$$\int{\left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)d x} = \frac{x^{6}}{90} - \frac{x^{4}}{12} + \frac{x^{2}}{2}$$
Añade la constante de integración:
$$\int{\left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)d x} = \frac{x^{6}}{90} - \frac{x^{4}}{12} + \frac{x^{2}}{2}+C$$
Respuesta
$$$\int \left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)\, dx = \left(\frac{x^{6}}{90} - \frac{x^{4}}{12} + \frac{x^{2}}{2}\right) + C$$$A