Integral de $$$- x^{2} + 2 x$$$

Halla $$$\int \left(- x^{2} + 2 x\right)\, dx$$$.

Integra término a término:

$${\color{red}{\int{\left(- x^{2} + 2 x\right)d x}}} = {\color{red}{\left(\int{2 x d x} - \int{x^{2} d x}\right)}}$$

Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=2$$$:

$$\int{2 x d x} - {\color{red}{\int{x^{2} d x}}}=\int{2 x d x} - {\color{red}{\frac{x^{1 + 2}}{1 + 2}}}=\int{2 x d x} - {\color{red}{\left(\frac{x^{3}}{3}\right)}}$$

Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=2$$$ y $$$f{\left(x \right)} = x$$$:

$$- \frac{x^{3}}{3} + {\color{red}{\int{2 x d x}}} = - \frac{x^{3}}{3} + {\color{red}{\left(2 \int{x d x}\right)}}$$

Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=1$$$:

$$- \frac{x^{3}}{3} + 2 {\color{red}{\int{x d x}}}=- \frac{x^{3}}{3} + 2 {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=- \frac{x^{3}}{3} + 2 {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

Por lo tanto,

$$\int{\left(- x^{2} + 2 x\right)d x} = - \frac{x^{3}}{3} + x^{2}$$

Simplificar:

$$\int{\left(- x^{2} + 2 x\right)d x} = \frac{x^{2} \left(3 - x\right)}{3}$$

Añade la constante de integración:

$$\int{\left(- x^{2} + 2 x\right)d x} = \frac{x^{2} \left(3 - x\right)}{3}+C$$

$$$\int \left(- x^{2} + 2 x\right)\, dx = \frac{x^{2} \left(3 - x\right)}{3} + C$$$A