Integral de $$$\sqrt{22} e^{x}$$$

Halla $$$\int \sqrt{22} e^{x}\, dx$$$.

Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=\sqrt{22}$$$ y $$$f{\left(x \right)} = e^{x}$$$:

$${\color{red}{\int{\sqrt{22} e^{x} d x}}} = {\color{red}{\sqrt{22} \int{e^{x} d x}}}$$

La integral de la función exponencial es $$$\int{e^{x} d x} = e^{x}$$$:

$$\sqrt{22} {\color{red}{\int{e^{x} d x}}} = \sqrt{22} {\color{red}{e^{x}}}$$

Por lo tanto,

$$\int{\sqrt{22} e^{x} d x} = \sqrt{22} e^{x}$$

Añade la constante de integración:

$$\int{\sqrt{22} e^{x} d x} = \sqrt{22} e^{x}+C$$

$$$\int \sqrt{22} e^{x}\, dx = \sqrt{22} e^{x} + C$$$A