Integral de $$$\frac{t}{e}$$$

Halla $$$\int \frac{t}{e}\, dt$$$.

Aplica la regla del factor constante $$$\int c f{\left(t \right)}\, dt = c \int f{\left(t \right)}\, dt$$$ con $$$c=e^{-1}$$$ y $$$f{\left(t \right)} = t$$$:

$${\color{red}{\int{\frac{t}{e} d t}}} = {\color{red}{\frac{\int{t d t}}{e}}}$$

Aplica la regla de la potencia $$$\int t^{n}\, dt = \frac{t^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=1$$$:

$$\frac{{\color{red}{\int{t d t}}}}{e}=\frac{{\color{red}{\frac{t^{1 + 1}}{1 + 1}}}}{e}=\frac{{\color{red}{\left(\frac{t^{2}}{2}\right)}}}{e}$$

Por lo tanto,

$$\int{\frac{t}{e} d t} = \frac{t^{2}}{2 e}$$

Añade la constante de integración:

$$\int{\frac{t}{e} d t} = \frac{t^{2}}{2 e}+C$$

$$$\int \frac{t}{e}\, dt = \frac{t^{2}}{2 e} + C$$$A