Integral de $$$- 37 e^{x} + \frac{37}{x}$$$
Calculadora relacionada: Calculadora de integrales definidas e impropias
Tu entrada
Halla $$$\int \left(- 37 e^{x} + \frac{37}{x}\right)\, dx$$$.
Solución
Integra término a término:
$${\color{red}{\int{\left(- 37 e^{x} + \frac{37}{x}\right)d x}}} = {\color{red}{\left(\int{\frac{37}{x} d x} - \int{37 e^{x} d x}\right)}}$$
Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=37$$$ y $$$f{\left(x \right)} = e^{x}$$$:
$$\int{\frac{37}{x} d x} - {\color{red}{\int{37 e^{x} d x}}} = \int{\frac{37}{x} d x} - {\color{red}{\left(37 \int{e^{x} d x}\right)}}$$
La integral de la función exponencial es $$$\int{e^{x} d x} = e^{x}$$$:
$$\int{\frac{37}{x} d x} - 37 {\color{red}{\int{e^{x} d x}}} = \int{\frac{37}{x} d x} - 37 {\color{red}{e^{x}}}$$
Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=37$$$ y $$$f{\left(x \right)} = \frac{1}{x}$$$:
$$- 37 e^{x} + {\color{red}{\int{\frac{37}{x} d x}}} = - 37 e^{x} + {\color{red}{\left(37 \int{\frac{1}{x} d x}\right)}}$$
La integral de $$$\frac{1}{x}$$$ es $$$\int{\frac{1}{x} d x} = \ln{\left(\left|{x}\right| \right)}$$$:
$$- 37 e^{x} + 37 {\color{red}{\int{\frac{1}{x} d x}}} = - 37 e^{x} + 37 {\color{red}{\ln{\left(\left|{x}\right| \right)}}}$$
Por lo tanto,
$$\int{\left(- 37 e^{x} + \frac{37}{x}\right)d x} = - 37 e^{x} + 37 \ln{\left(\left|{x}\right| \right)}$$
Añade la constante de integración:
$$\int{\left(- 37 e^{x} + \frac{37}{x}\right)d x} = - 37 e^{x} + 37 \ln{\left(\left|{x}\right| \right)}+C$$
Respuesta
$$$\int \left(- 37 e^{x} + \frac{37}{x}\right)\, dx = \left(- 37 e^{x} + 37 \ln\left(\left|{x}\right|\right)\right) + C$$$A