Integral de $$$2 e^{2 y}$$$

Halla $$$\int 2 e^{2 y}\, dy$$$.

Aplica la regla del factor constante $$$\int c f{\left(y \right)}\, dy = c \int f{\left(y \right)}\, dy$$$ con $$$c=2$$$ y $$$f{\left(y \right)} = e^{2 y}$$$:

$${\color{red}{\int{2 e^{2 y} d y}}} = {\color{red}{\left(2 \int{e^{2 y} d y}\right)}}$$

Sea $$$u=2 y$$$.

Entonces $$$du=\left(2 y\right)^{\prime }dy = 2 dy$$$ (los pasos pueden verse »), y obtenemos que $$$dy = \frac{du}{2}$$$.

La integral puede reescribirse como

$$2 {\color{red}{\int{e^{2 y} d y}}} = 2 {\color{red}{\int{\frac{e^{u}}{2} d u}}}$$

Aplica la regla del factor constante $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ con $$$c=\frac{1}{2}$$$ y $$$f{\left(u \right)} = e^{u}$$$:

$$2 {\color{red}{\int{\frac{e^{u}}{2} d u}}} = 2 {\color{red}{\left(\frac{\int{e^{u} d u}}{2}\right)}}$$

La integral de la función exponencial es $$$\int{e^{u} d u} = e^{u}$$$:

$${\color{red}{\int{e^{u} d u}}} = {\color{red}{e^{u}}}$$

Recordemos que $$$u=2 y$$$:

$$e^{{\color{red}{u}}} = e^{{\color{red}{\left(2 y\right)}}}$$

Por lo tanto,

$$\int{2 e^{2 y} d y} = e^{2 y}$$

Añade la constante de integración:

$$\int{2 e^{2 y} d y} = e^{2 y}+C$$

$$$\int 2 e^{2 y}\, dy = e^{2 y} + C$$$A