Integral de $$$160 t^{3}$$$

Halla $$$\int 160 t^{3}\, dt$$$.

Aplica la regla del factor constante $$$\int c f{\left(t \right)}\, dt = c \int f{\left(t \right)}\, dt$$$ con $$$c=160$$$ y $$$f{\left(t \right)} = t^{3}$$$:

$${\color{red}{\int{160 t^{3} d t}}} = {\color{red}{\left(160 \int{t^{3} d t}\right)}}$$

Aplica la regla de la potencia $$$\int t^{n}\, dt = \frac{t^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=3$$$:

$$160 {\color{red}{\int{t^{3} d t}}}=160 {\color{red}{\frac{t^{1 + 3}}{1 + 3}}}=160 {\color{red}{\left(\frac{t^{4}}{4}\right)}}$$

Por lo tanto,

$$\int{160 t^{3} d t} = 40 t^{4}$$

Añade la constante de integración:

$$\int{160 t^{3} d t} = 40 t^{4}+C$$

$$$\int 160 t^{3}\, dt = 40 t^{4} + C$$$A