Integral de $$$i n t x^{42}$$$ con respecto a $$$x$$$

Halla $$$\int i n t x^{42}\, dx$$$.

Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=i n t$$$ y $$$f{\left(x \right)} = x^{42}$$$:

$${\color{red}{\int{i n t x^{42} d x}}} = {\color{red}{i n t \int{x^{42} d x}}}$$

Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=42$$$:

$$i n t {\color{red}{\int{x^{42} d x}}}=i n t {\color{red}{\frac{x^{1 + 42}}{1 + 42}}}=i n t {\color{red}{\left(\frac{x^{43}}{43}\right)}}$$

Por lo tanto,

$$\int{i n t x^{42} d x} = \frac{i n t x^{43}}{43}$$

Añade la constante de integración:

$$\int{i n t x^{42} d x} = \frac{i n t x^{43}}{43}+C$$

$$$\int i n t x^{42}\, dx = \frac{i n t x^{43}}{43} + C$$$A