Integral de $$$\frac{y}{12}$$$

Halla $$$\int \frac{y}{12}\, dy$$$.

Aplica la regla del factor constante $$$\int c f{\left(y \right)}\, dy = c \int f{\left(y \right)}\, dy$$$ con $$$c=\frac{1}{12}$$$ y $$$f{\left(y \right)} = y$$$:

$${\color{red}{\int{\frac{y}{12} d y}}} = {\color{red}{\left(\frac{\int{y d y}}{12}\right)}}$$

Aplica la regla de la potencia $$$\int y^{n}\, dy = \frac{y^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=1$$$:

$$\frac{{\color{red}{\int{y d y}}}}{12}=\frac{{\color{red}{\frac{y^{1 + 1}}{1 + 1}}}}{12}=\frac{{\color{red}{\left(\frac{y^{2}}{2}\right)}}}{12}$$

Por lo tanto,

$$\int{\frac{y}{12} d y} = \frac{y^{2}}{24}$$

Añade la constante de integración:

$$\int{\frac{y}{12} d y} = \frac{y^{2}}{24}+C$$

$$$\int \frac{y}{12}\, dy = \frac{y^{2}}{24} + C$$$A