Integral de $$$5 x^{38} \left(6 x^{3} - 9\right)$$$

La calculadora encontrará la integral/antiderivada de $$$5 x^{38} \left(6 x^{3} - 9\right)$$$, mostrando los pasos.

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Tu entrada

Halla $$$\int 5 x^{38} \left(6 x^{3} - 9\right)\, dx$$$.

Solución

La entrada se reescribe: $$$\int{5 x^{38} \left(6 x^{3} - 9\right) d x}=\int{x^{38} \left(30 x^{3} - 45\right) d x}$$$.

Simplificar el integrando:

$${\color{red}{\int{x^{38} \left(30 x^{3} - 45\right) d x}}} = {\color{red}{\int{15 x^{38} \left(2 x^{3} - 3\right) d x}}}$$

Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=15$$$ y $$$f{\left(x \right)} = x^{38} \left(2 x^{3} - 3\right)$$$:

$${\color{red}{\int{15 x^{38} \left(2 x^{3} - 3\right) d x}}} = {\color{red}{\left(15 \int{x^{38} \left(2 x^{3} - 3\right) d x}\right)}}$$

Expand the expression:

$$15 {\color{red}{\int{x^{38} \left(2 x^{3} - 3\right) d x}}} = 15 {\color{red}{\int{\left(2 x^{41} - 3 x^{38}\right)d x}}}$$

Integra término a término:

$$15 {\color{red}{\int{\left(2 x^{41} - 3 x^{38}\right)d x}}} = 15 {\color{red}{\left(- \int{3 x^{38} d x} + \int{2 x^{41} d x}\right)}}$$

Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=3$$$ y $$$f{\left(x \right)} = x^{38}$$$:

$$15 \int{2 x^{41} d x} - 15 {\color{red}{\int{3 x^{38} d x}}} = 15 \int{2 x^{41} d x} - 15 {\color{red}{\left(3 \int{x^{38} d x}\right)}}$$

Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=38$$$:

$$15 \int{2 x^{41} d x} - 45 {\color{red}{\int{x^{38} d x}}}=15 \int{2 x^{41} d x} - 45 {\color{red}{\frac{x^{1 + 38}}{1 + 38}}}=15 \int{2 x^{41} d x} - 45 {\color{red}{\left(\frac{x^{39}}{39}\right)}}$$

Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=2$$$ y $$$f{\left(x \right)} = x^{41}$$$:

$$- \frac{15 x^{39}}{13} + 15 {\color{red}{\int{2 x^{41} d x}}} = - \frac{15 x^{39}}{13} + 15 {\color{red}{\left(2 \int{x^{41} d x}\right)}}$$

Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=41$$$:

$$- \frac{15 x^{39}}{13} + 30 {\color{red}{\int{x^{41} d x}}}=- \frac{15 x^{39}}{13} + 30 {\color{red}{\frac{x^{1 + 41}}{1 + 41}}}=- \frac{15 x^{39}}{13} + 30 {\color{red}{\left(\frac{x^{42}}{42}\right)}}$$

Por lo tanto,

$$\int{x^{38} \left(30 x^{3} - 45\right) d x} = \frac{5 x^{42}}{7} - \frac{15 x^{39}}{13}$$

Simplificar:

$$\int{x^{38} \left(30 x^{3} - 45\right) d x} = \frac{5 x^{39} \left(13 x^{3} - 21\right)}{91}$$

Añade la constante de integración:

$$\int{x^{38} \left(30 x^{3} - 45\right) d x} = \frac{5 x^{39} \left(13 x^{3} - 21\right)}{91}+C$$

Respuesta

$$$\int 5 x^{38} \left(6 x^{3} - 9\right)\, dx = \frac{5 x^{39} \left(13 x^{3} - 21\right)}{91} + C$$$A


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