Integral de $$$\frac{x^{2} + 1}{\left(x^{2} + 2\right) \left(x^{2} + 3\right)}$$$

La calculadora encontrará la integral/antiderivada de $$$\frac{x^{2} + 1}{\left(x^{2} + 2\right) \left(x^{2} + 3\right)}$$$, mostrando los pasos.

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Tu entrada

Halla $$$\int \frac{x^{2} + 1}{\left(x^{2} + 2\right) \left(x^{2} + 3\right)}\, dx$$$.

Solución

Realizar la descomposición en fracciones parciales (los pasos pueden verse »):

$${\color{red}{\int{\frac{x^{2} + 1}{\left(x^{2} + 2\right) \left(x^{2} + 3\right)} d x}}} = {\color{red}{\int{\left(\frac{2}{x^{2} + 3} - \frac{1}{x^{2} + 2}\right)d x}}}$$

Integra término a término:

$${\color{red}{\int{\left(\frac{2}{x^{2} + 3} - \frac{1}{x^{2} + 2}\right)d x}}} = {\color{red}{\left(- \int{\frac{1}{x^{2} + 2} d x} + \int{\frac{2}{x^{2} + 3} d x}\right)}}$$

Sea $$$u=\frac{\sqrt{2}}{2} x$$$.

Entonces $$$du=\left(\frac{\sqrt{2}}{2} x\right)^{\prime }dx = \frac{\sqrt{2}}{2} dx$$$ (los pasos pueden verse »), y obtenemos que $$$dx = \sqrt{2} du$$$.

La integral se convierte en

$$\int{\frac{2}{x^{2} + 3} d x} - {\color{red}{\int{\frac{1}{x^{2} + 2} d x}}} = \int{\frac{2}{x^{2} + 3} d x} - {\color{red}{\int{\frac{\sqrt{2}}{2 \left(u^{2} + 1\right)} d u}}}$$

Aplica la regla del factor constante $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ con $$$c=\frac{\sqrt{2}}{2}$$$ y $$$f{\left(u \right)} = \frac{1}{u^{2} + 1}$$$:

$$\int{\frac{2}{x^{2} + 3} d x} - {\color{red}{\int{\frac{\sqrt{2}}{2 \left(u^{2} + 1\right)} d u}}} = \int{\frac{2}{x^{2} + 3} d x} - {\color{red}{\left(\frac{\sqrt{2} \int{\frac{1}{u^{2} + 1} d u}}{2}\right)}}$$

La integral de $$$\frac{1}{u^{2} + 1}$$$ es $$$\int{\frac{1}{u^{2} + 1} d u} = \operatorname{atan}{\left(u \right)}$$$:

$$\int{\frac{2}{x^{2} + 3} d x} - \frac{\sqrt{2} {\color{red}{\int{\frac{1}{u^{2} + 1} d u}}}}{2} = \int{\frac{2}{x^{2} + 3} d x} - \frac{\sqrt{2} {\color{red}{\operatorname{atan}{\left(u \right)}}}}{2}$$

Recordemos que $$$u=\frac{\sqrt{2}}{2} x$$$:

$$\int{\frac{2}{x^{2} + 3} d x} - \frac{\sqrt{2} \operatorname{atan}{\left({\color{red}{u}} \right)}}{2} = \int{\frac{2}{x^{2} + 3} d x} - \frac{\sqrt{2} \operatorname{atan}{\left({\color{red}{\frac{\sqrt{2}}{2} x}} \right)}}{2}$$

Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=2$$$ y $$$f{\left(x \right)} = \frac{1}{x^{2} + 3}$$$:

$$- \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + {\color{red}{\int{\frac{2}{x^{2} + 3} d x}}} = - \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + {\color{red}{\left(2 \int{\frac{1}{x^{2} + 3} d x}\right)}}$$

Sea $$$u=\frac{\sqrt{3}}{3} x$$$.

Entonces $$$du=\left(\frac{\sqrt{3}}{3} x\right)^{\prime }dx = \frac{\sqrt{3}}{3} dx$$$ (los pasos pueden verse »), y obtenemos que $$$dx = \sqrt{3} du$$$.

La integral puede reescribirse como

$$- \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + 2 {\color{red}{\int{\frac{1}{x^{2} + 3} d x}}} = - \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + 2 {\color{red}{\int{\frac{\sqrt{3}}{3 \left(u^{2} + 1\right)} d u}}}$$

Aplica la regla del factor constante $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ con $$$c=\frac{\sqrt{3}}{3}$$$ y $$$f{\left(u \right)} = \frac{1}{u^{2} + 1}$$$:

$$- \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + 2 {\color{red}{\int{\frac{\sqrt{3}}{3 \left(u^{2} + 1\right)} d u}}} = - \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + 2 {\color{red}{\left(\frac{\sqrt{3} \int{\frac{1}{u^{2} + 1} d u}}{3}\right)}}$$

La integral de $$$\frac{1}{u^{2} + 1}$$$ es $$$\int{\frac{1}{u^{2} + 1} d u} = \operatorname{atan}{\left(u \right)}$$$:

$$- \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + \frac{2 \sqrt{3} {\color{red}{\int{\frac{1}{u^{2} + 1} d u}}}}{3} = - \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + \frac{2 \sqrt{3} {\color{red}{\operatorname{atan}{\left(u \right)}}}}{3}$$

Recordemos que $$$u=\frac{\sqrt{3}}{3} x$$$:

$$- \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + \frac{2 \sqrt{3} \operatorname{atan}{\left({\color{red}{u}} \right)}}{3} = - \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2}}{2} x \right)}}{2} + \frac{2 \sqrt{3} \operatorname{atan}{\left({\color{red}{\frac{\sqrt{3}}{3} x}} \right)}}{3}$$

Por lo tanto,

$$\int{\frac{x^{2} + 1}{\left(x^{2} + 2\right) \left(x^{2} + 3\right)} d x} = - \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2} x}{2} \right)}}{2} + \frac{2 \sqrt{3} \operatorname{atan}{\left(\frac{\sqrt{3} x}{3} \right)}}{3}$$

Añade la constante de integración:

$$\int{\frac{x^{2} + 1}{\left(x^{2} + 2\right) \left(x^{2} + 3\right)} d x} = - \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2} x}{2} \right)}}{2} + \frac{2 \sqrt{3} \operatorname{atan}{\left(\frac{\sqrt{3} x}{3} \right)}}{3}+C$$

Respuesta

$$$\int \frac{x^{2} + 1}{\left(x^{2} + 2\right) \left(x^{2} + 3\right)}\, dx = \left(- \frac{\sqrt{2} \operatorname{atan}{\left(\frac{\sqrt{2} x}{2} \right)}}{2} + \frac{2 \sqrt{3} \operatorname{atan}{\left(\frac{\sqrt{3} x}{3} \right)}}{3}\right) + C$$$A