# Prime factorization of $920$

The calculator will find the prime factorization of $920$, with steps shown.

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Find the prime factorization of $920$.

### Solution

Start with the number $2$.

Determine whether $920$ is divisible by $2$.

It is divisible, thus, divide $920$ by ${\color{green}2}$: $\frac{920}{2} = {\color{red}460}$.

Determine whether $460$ is divisible by $2$.

It is divisible, thus, divide $460$ by ${\color{green}2}$: $\frac{460}{2} = {\color{red}230}$.

Determine whether $230$ is divisible by $2$.

It is divisible, thus, divide $230$ by ${\color{green}2}$: $\frac{230}{2} = {\color{red}115}$.

Determine whether $115$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $115$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $115$ is divisible by $5$.

It is divisible, thus, divide $115$ by ${\color{green}5}$: $\frac{115}{5} = {\color{red}23}$.

The prime number ${\color{green}23}$ has no other factors then $1$ and ${\color{green}23}$: $\frac{23}{23} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $920 = 2^{3} \cdot 5 \cdot 23$.

The prime factorization is $920 = 2^{3} \cdot 5 \cdot 23$A.