Prime factorization of $$$916$$$

Find the prime factorization of $$$916$$$.

Start with the number $$$2$$$.

Determine whether $$$916$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$916$$$ by $$${\color{green}2}$$$: $$$\frac{916}{2} = {\color{red}458}$$$.

Determine whether $$$458$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$458$$$ by $$${\color{green}2}$$$: $$$\frac{458}{2} = {\color{red}229}$$$.

The prime number $$${\color{green}229}$$$ has no other factors then $$$1$$$ and $$${\color{green}229}$$$: $$$\frac{229}{229} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$916 = 2^{2} \cdot 229$$$.

The prime factorization is $$$916 = 2^{2} \cdot 229$$$A.