# Prime factorization of $912$

The calculator will find the prime factorization of $912$, with steps shown.

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Find the prime factorization of $912$.

### Solution

Start with the number $2$.

Determine whether $912$ is divisible by $2$.

It is divisible, thus, divide $912$ by ${\color{green}2}$: $\frac{912}{2} = {\color{red}456}$.

Determine whether $456$ is divisible by $2$.

It is divisible, thus, divide $456$ by ${\color{green}2}$: $\frac{456}{2} = {\color{red}228}$.

Determine whether $228$ is divisible by $2$.

It is divisible, thus, divide $228$ by ${\color{green}2}$: $\frac{228}{2} = {\color{red}114}$.

Determine whether $114$ is divisible by $2$.

It is divisible, thus, divide $114$ by ${\color{green}2}$: $\frac{114}{2} = {\color{red}57}$.

Determine whether $57$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $57$ is divisible by $3$.

It is divisible, thus, divide $57$ by ${\color{green}3}$: $\frac{57}{3} = {\color{red}19}$.

The prime number ${\color{green}19}$ has no other factors then $1$ and ${\color{green}19}$: $\frac{19}{19} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $912 = 2^{4} \cdot 3 \cdot 19$.

The prime factorization is $912 = 2^{4} \cdot 3 \cdot 19$A.