Prime factorization of $$$4996$$$

Find the prime factorization of $$$4996$$$.

Start with the number $$$2$$$.

Determine whether $$$4996$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4996$$$ by $$${\color{green}2}$$$: $$$\frac{4996}{2} = {\color{red}2498}$$$.

Determine whether $$$2498$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2498$$$ by $$${\color{green}2}$$$: $$$\frac{2498}{2} = {\color{red}1249}$$$.

The prime number $$${\color{green}1249}$$$ has no other factors then $$$1$$$ and $$${\color{green}1249}$$$: $$$\frac{1249}{1249} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4996 = 2^{2} \cdot 1249$$$.

The prime factorization is $$$4996 = 2^{2} \cdot 1249$$$A.