# Prime factorization of $4936$

The calculator will find the prime factorization of $4936$, with steps shown.

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Find the prime factorization of $4936$.

### Solution

Start with the number $2$.

Determine whether $4936$ is divisible by $2$.

It is divisible, thus, divide $4936$ by ${\color{green}2}$: $\frac{4936}{2} = {\color{red}2468}$.

Determine whether $2468$ is divisible by $2$.

It is divisible, thus, divide $2468$ by ${\color{green}2}$: $\frac{2468}{2} = {\color{red}1234}$.

Determine whether $1234$ is divisible by $2$.

It is divisible, thus, divide $1234$ by ${\color{green}2}$: $\frac{1234}{2} = {\color{red}617}$.

The prime number ${\color{green}617}$ has no other factors then $1$ and ${\color{green}617}$: $\frac{617}{617} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $4936 = 2^{3} \cdot 617$.

The prime factorization is $4936 = 2^{3} \cdot 617$A.