Prime factorization of $$$4923$$$

Find the prime factorization of $$$4923$$$.

Start with the number $$$2$$$.

Determine whether $$$4923$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$4923$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$4923$$$ by $$${\color{green}3}$$$: $$$\frac{4923}{3} = {\color{red}1641}$$$.

Determine whether $$$1641$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$1641$$$ by $$${\color{green}3}$$$: $$$\frac{1641}{3} = {\color{red}547}$$$.

The prime number $$${\color{green}547}$$$ has no other factors then $$$1$$$ and $$${\color{green}547}$$$: $$$\frac{547}{547} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4923 = 3^{2} \cdot 547$$$.

The prime factorization is $$$4923 = 3^{2} \cdot 547$$$A.