Prime factorization of $$$4856$$$

Find the prime factorization of $$$4856$$$.

Start with the number $$$2$$$.

Determine whether $$$4856$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4856$$$ by $$${\color{green}2}$$$: $$$\frac{4856}{2} = {\color{red}2428}$$$.

Determine whether $$$2428$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2428$$$ by $$${\color{green}2}$$$: $$$\frac{2428}{2} = {\color{red}1214}$$$.

Determine whether $$$1214$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1214$$$ by $$${\color{green}2}$$$: $$$\frac{1214}{2} = {\color{red}607}$$$.

The prime number $$${\color{green}607}$$$ has no other factors then $$$1$$$ and $$${\color{green}607}$$$: $$$\frac{607}{607} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4856 = 2^{3} \cdot 607$$$.

The prime factorization is $$$4856 = 2^{3} \cdot 607$$$A.