Prime factorization of $$$4820$$$

Find the prime factorization of $$$4820$$$.

Start with the number $$$2$$$.

Determine whether $$$4820$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4820$$$ by $$${\color{green}2}$$$: $$$\frac{4820}{2} = {\color{red}2410}$$$.

Determine whether $$$2410$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2410$$$ by $$${\color{green}2}$$$: $$$\frac{2410}{2} = {\color{red}1205}$$$.

Determine whether $$$1205$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$1205$$$ is divisible by $$$3$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$5$$$.

Determine whether $$$1205$$$ is divisible by $$$5$$$.

It is divisible, thus, divide $$$1205$$$ by $$${\color{green}5}$$$: $$$\frac{1205}{5} = {\color{red}241}$$$.

The prime number $$${\color{green}241}$$$ has no other factors then $$$1$$$ and $$${\color{green}241}$$$: $$$\frac{241}{241} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4820 = 2^{2} \cdot 5 \cdot 241$$$.

The prime factorization is $$$4820 = 2^{2} \cdot 5 \cdot 241$$$A.