Prime factorization of $$$4476$$$
Your Input
Find the prime factorization of $$$4476$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$4476$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$4476$$$ by $$${\color{green}2}$$$: $$$\frac{4476}{2} = {\color{red}2238}$$$.
Determine whether $$$2238$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$2238$$$ by $$${\color{green}2}$$$: $$$\frac{2238}{2} = {\color{red}1119}$$$.
Determine whether $$$1119$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1119$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$1119$$$ by $$${\color{green}3}$$$: $$$\frac{1119}{3} = {\color{red}373}$$$.
The prime number $$${\color{green}373}$$$ has no other factors then $$$1$$$ and $$${\color{green}373}$$$: $$$\frac{373}{373} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4476 = 2^{2} \cdot 3 \cdot 373$$$.
Answer
The prime factorization is $$$4476 = 2^{2} \cdot 3 \cdot 373$$$A.