Prime factorization of $$$4412$$$

Find the prime factorization of $$$4412$$$.

Start with the number $$$2$$$.

Determine whether $$$4412$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4412$$$ by $$${\color{green}2}$$$: $$$\frac{4412}{2} = {\color{red}2206}$$$.

Determine whether $$$2206$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2206$$$ by $$${\color{green}2}$$$: $$$\frac{2206}{2} = {\color{red}1103}$$$.

The prime number $$${\color{green}1103}$$$ has no other factors then $$$1$$$ and $$${\color{green}1103}$$$: $$$\frac{1103}{1103} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4412 = 2^{2} \cdot 1103$$$.

The prime factorization is $$$4412 = 2^{2} \cdot 1103$$$A.