Prime factorization of $$$4311$$$

Find the prime factorization of $$$4311$$$.

Start with the number $$$2$$$.

Determine whether $$$4311$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$4311$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$4311$$$ by $$${\color{green}3}$$$: $$$\frac{4311}{3} = {\color{red}1437}$$$.

Determine whether $$$1437$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$1437$$$ by $$${\color{green}3}$$$: $$$\frac{1437}{3} = {\color{red}479}$$$.

The prime number $$${\color{green}479}$$$ has no other factors then $$$1$$$ and $$${\color{green}479}$$$: $$$\frac{479}{479} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4311 = 3^{2} \cdot 479$$$.

The prime factorization is $$$4311 = 3^{2} \cdot 479$$$A.