# Prime factorization of $4310$

The calculator will find the prime factorization of $4310$, with steps shown.

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Find the prime factorization of $4310$.

### Solution

Start with the number $2$.

Determine whether $4310$ is divisible by $2$.

It is divisible, thus, divide $4310$ by ${\color{green}2}$: $\frac{4310}{2} = {\color{red}2155}$.

Determine whether $2155$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $2155$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $2155$ is divisible by $5$.

It is divisible, thus, divide $2155$ by ${\color{green}5}$: $\frac{2155}{5} = {\color{red}431}$.

The prime number ${\color{green}431}$ has no other factors then $1$ and ${\color{green}431}$: $\frac{431}{431} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $4310 = 2 \cdot 5 \cdot 431$.

The prime factorization is $4310 = 2 \cdot 5 \cdot 431$A.