Prime factorization of $$$4310$$$

Find the prime factorization of $$$4310$$$.

Start with the number $$$2$$$.

Determine whether $$$4310$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4310$$$ by $$${\color{green}2}$$$: $$$\frac{4310}{2} = {\color{red}2155}$$$.

Determine whether $$$2155$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$2155$$$ is divisible by $$$3$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$5$$$.

Determine whether $$$2155$$$ is divisible by $$$5$$$.

It is divisible, thus, divide $$$2155$$$ by $$${\color{green}5}$$$: $$$\frac{2155}{5} = {\color{red}431}$$$.

The prime number $$${\color{green}431}$$$ has no other factors then $$$1$$$ and $$${\color{green}431}$$$: $$$\frac{431}{431} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4310 = 2 \cdot 5 \cdot 431$$$.

The prime factorization is $$$4310 = 2 \cdot 5 \cdot 431$$$A.