# Prime factorization of $423$

The calculator will find the prime factorization of $423$, with steps shown.

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Find the prime factorization of $423$.

### Solution

Start with the number $2$.

Determine whether $423$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $423$ is divisible by $3$.

It is divisible, thus, divide $423$ by ${\color{green}3}$: $\frac{423}{3} = {\color{red}141}$.

Determine whether $141$ is divisible by $3$.

It is divisible, thus, divide $141$ by ${\color{green}3}$: $\frac{141}{3} = {\color{red}47}$.

The prime number ${\color{green}47}$ has no other factors then $1$ and ${\color{green}47}$: $\frac{47}{47} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $423 = 3^{2} \cdot 47$.

The prime factorization is $423 = 3^{2} \cdot 47$A.