Prime factorization of $$$4022$$$

Find the prime factorization of $$$4022$$$.

Start with the number $$$2$$$.

Determine whether $$$4022$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4022$$$ by $$${\color{green}2}$$$: $$$\frac{4022}{2} = {\color{red}2011}$$$.

The prime number $$${\color{green}2011}$$$ has no other factors then $$$1$$$ and $$${\color{green}2011}$$$: $$$\frac{2011}{2011} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4022 = 2 \cdot 2011$$$.

The prime factorization is $$$4022 = 2 \cdot 2011$$$A.