Prime factorization of $$$3950$$$
Your Input
Find the prime factorization of $$$3950$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3950$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$3950$$$ by $$${\color{green}2}$$$: $$$\frac{3950}{2} = {\color{red}1975}$$$.
Determine whether $$$1975$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1975$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$1975$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$1975$$$ by $$${\color{green}5}$$$: $$$\frac{1975}{5} = {\color{red}395}$$$.
Determine whether $$$395$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$395$$$ by $$${\color{green}5}$$$: $$$\frac{395}{5} = {\color{red}79}$$$.
The prime number $$${\color{green}79}$$$ has no other factors then $$$1$$$ and $$${\color{green}79}$$$: $$$\frac{79}{79} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3950 = 2 \cdot 5^{2} \cdot 79$$$.
Answer
The prime factorization is $$$3950 = 2 \cdot 5^{2} \cdot 79$$$A.