# Prime factorization of $3932$

The calculator will find the prime factorization of $3932$, with steps shown.

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Find the prime factorization of $3932$.

### Solution

Start with the number $2$.

Determine whether $3932$ is divisible by $2$.

It is divisible, thus, divide $3932$ by ${\color{green}2}$: $\frac{3932}{2} = {\color{red}1966}$.

Determine whether $1966$ is divisible by $2$.

It is divisible, thus, divide $1966$ by ${\color{green}2}$: $\frac{1966}{2} = {\color{red}983}$.

The prime number ${\color{green}983}$ has no other factors then $1$ and ${\color{green}983}$: $\frac{983}{983} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3932 = 2^{2} \cdot 983$.

The prime factorization is $3932 = 2^{2} \cdot 983$A.