Prime factorization of $$$3711$$$

Find the prime factorization of $$$3711$$$.

Start with the number $$$2$$$.

Determine whether $$$3711$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$3711$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$3711$$$ by $$${\color{green}3}$$$: $$$\frac{3711}{3} = {\color{red}1237}$$$.

The prime number $$${\color{green}1237}$$$ has no other factors then $$$1$$$ and $$${\color{green}1237}$$$: $$$\frac{1237}{1237} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3711 = 3 \cdot 1237$$$.

The prime factorization is $$$3711 = 3 \cdot 1237$$$A.