Prime factorization of $$$3693$$$

Find the prime factorization of $$$3693$$$.

Start with the number $$$2$$$.

Determine whether $$$3693$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$3693$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$3693$$$ by $$${\color{green}3}$$$: $$$\frac{3693}{3} = {\color{red}1231}$$$.

The prime number $$${\color{green}1231}$$$ has no other factors then $$$1$$$ and $$${\color{green}1231}$$$: $$$\frac{1231}{1231} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3693 = 3 \cdot 1231$$$.

The prime factorization is $$$3693 = 3 \cdot 1231$$$A.