# Prime factorization of $3537$

The calculator will find the prime factorization of $3537$, with steps shown.

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Find the prime factorization of $3537$.

### Solution

Start with the number $2$.

Determine whether $3537$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $3537$ is divisible by $3$.

It is divisible, thus, divide $3537$ by ${\color{green}3}$: $\frac{3537}{3} = {\color{red}1179}$.

Determine whether $1179$ is divisible by $3$.

It is divisible, thus, divide $1179$ by ${\color{green}3}$: $\frac{1179}{3} = {\color{red}393}$.

Determine whether $393$ is divisible by $3$.

It is divisible, thus, divide $393$ by ${\color{green}3}$: $\frac{393}{3} = {\color{red}131}$.

The prime number ${\color{green}131}$ has no other factors then $1$ and ${\color{green}131}$: $\frac{131}{131} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3537 = 3^{3} \cdot 131$.

The prime factorization is $3537 = 3^{3} \cdot 131$A.