Prime factorization of $$$3532$$$

Find the prime factorization of $$$3532$$$.

Start with the number $$$2$$$.

Determine whether $$$3532$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$3532$$$ by $$${\color{green}2}$$$: $$$\frac{3532}{2} = {\color{red}1766}$$$.

Determine whether $$$1766$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1766$$$ by $$${\color{green}2}$$$: $$$\frac{1766}{2} = {\color{red}883}$$$.

The prime number $$${\color{green}883}$$$ has no other factors then $$$1$$$ and $$${\color{green}883}$$$: $$$\frac{883}{883} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3532 = 2^{2} \cdot 883$$$.

The prime factorization is $$$3532 = 2^{2} \cdot 883$$$A.