Prime factorization of $$$344$$$
Your Input
Find the prime factorization of $$$344$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$344$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$344$$$ by $$${\color{green}2}$$$: $$$\frac{344}{2} = {\color{red}172}$$$.
Determine whether $$$172$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$172$$$ by $$${\color{green}2}$$$: $$$\frac{172}{2} = {\color{red}86}$$$.
Determine whether $$$86$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$86$$$ by $$${\color{green}2}$$$: $$$\frac{86}{2} = {\color{red}43}$$$.
The prime number $$${\color{green}43}$$$ has no other factors then $$$1$$$ and $$${\color{green}43}$$$: $$$\frac{43}{43} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$344 = 2^{3} \cdot 43$$$.
Answer
The prime factorization is $$$344 = 2^{3} \cdot 43$$$A.