Prime factorization of $$$3436$$$

Find the prime factorization of $$$3436$$$.

Start with the number $$$2$$$.

Determine whether $$$3436$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$3436$$$ by $$${\color{green}2}$$$: $$$\frac{3436}{2} = {\color{red}1718}$$$.

Determine whether $$$1718$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1718$$$ by $$${\color{green}2}$$$: $$$\frac{1718}{2} = {\color{red}859}$$$.

The prime number $$${\color{green}859}$$$ has no other factors then $$$1$$$ and $$${\color{green}859}$$$: $$$\frac{859}{859} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3436 = 2^{2} \cdot 859$$$.

The prime factorization is $$$3436 = 2^{2} \cdot 859$$$A.