# Prime factorization of $3285$

The calculator will find the prime factorization of $3285$, with steps shown.

If the calculator did not compute something or you have identified an error, or you have a suggestion/feedback, please write it in the comments below.

Find the prime factorization of $3285$.

### Solution

Start with the number $2$.

Determine whether $3285$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $3285$ is divisible by $3$.

It is divisible, thus, divide $3285$ by ${\color{green}3}$: $\frac{3285}{3} = {\color{red}1095}$.

Determine whether $1095$ is divisible by $3$.

It is divisible, thus, divide $1095$ by ${\color{green}3}$: $\frac{1095}{3} = {\color{red}365}$.

Determine whether $365$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $365$ is divisible by $5$.

It is divisible, thus, divide $365$ by ${\color{green}5}$: $\frac{365}{5} = {\color{red}73}$.

The prime number ${\color{green}73}$ has no other factors then $1$ and ${\color{green}73}$: $\frac{73}{73} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3285 = 3^{2} \cdot 5 \cdot 73$.

The prime factorization is $3285 = 3^{2} \cdot 5 \cdot 73$A.