# Prime factorization of $3220$

The calculator will find the prime factorization of $3220$, with steps shown.

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Find the prime factorization of $3220$.

### Solution

Start with the number $2$.

Determine whether $3220$ is divisible by $2$.

It is divisible, thus, divide $3220$ by ${\color{green}2}$: $\frac{3220}{2} = {\color{red}1610}$.

Determine whether $1610$ is divisible by $2$.

It is divisible, thus, divide $1610$ by ${\color{green}2}$: $\frac{1610}{2} = {\color{red}805}$.

Determine whether $805$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $805$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $805$ is divisible by $5$.

It is divisible, thus, divide $805$ by ${\color{green}5}$: $\frac{805}{5} = {\color{red}161}$.

Determine whether $161$ is divisible by $5$.

Since it is not divisible, move to the next prime number.

The next prime number is $7$.

Determine whether $161$ is divisible by $7$.

It is divisible, thus, divide $161$ by ${\color{green}7}$: $\frac{161}{7} = {\color{red}23}$.

The prime number ${\color{green}23}$ has no other factors then $1$ and ${\color{green}23}$: $\frac{23}{23} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3220 = 2^{2} \cdot 5 \cdot 7 \cdot 23$.

The prime factorization is $3220 = 2^{2} \cdot 5 \cdot 7 \cdot 23$A.