Prime factorization of $$$3213$$$
Your Input
Find the prime factorization of $$$3213$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3213$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$3213$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$3213$$$ by $$${\color{green}3}$$$: $$$\frac{3213}{3} = {\color{red}1071}$$$.
Determine whether $$$1071$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$1071$$$ by $$${\color{green}3}$$$: $$$\frac{1071}{3} = {\color{red}357}$$$.
Determine whether $$$357$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$357$$$ by $$${\color{green}3}$$$: $$$\frac{357}{3} = {\color{red}119}$$$.
Determine whether $$$119$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$119$$$ is divisible by $$$5$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$7$$$.
Determine whether $$$119$$$ is divisible by $$$7$$$.
It is divisible, thus, divide $$$119$$$ by $$${\color{green}7}$$$: $$$\frac{119}{7} = {\color{red}17}$$$.
The prime number $$${\color{green}17}$$$ has no other factors then $$$1$$$ and $$${\color{green}17}$$$: $$$\frac{17}{17} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3213 = 3^{3} \cdot 7 \cdot 17$$$.
Answer
The prime factorization is $$$3213 = 3^{3} \cdot 7 \cdot 17$$$A.